Mark Wilson (mmwilson2@earthlink.net)
Wed, 8 Nov 2000 6:0:10 0500
> [Original Message]
> From: Z <z@gundam.com>
> To: <gundam@aeug.org>
> Date: 11/8/00 1:47:42 AM
> Subject: RE: [gundam] Gravity within a colony (was: Funnels and flying MS)
>
>
>
> > Original Message
> > From: ownergundam@1u.aeug.org [mailto:ownergundam@1u.aeug.org]On
> > Behalf Of Z
> > Sent: Tuesday, November 07, 2000 22:29
> > To: gundam@aeug.org
> > Subject: RE: [gundam] Gravity within a colony (was: Funnels and flying
> > MS)
> >
> >
> > > Original Message
> > > From: ownergundam@1u.aeug.org [mailto:ownergundam@1u.aeug.org]On
> > > Behalf Of Vince Leon
> > > Sent: Tuesday, November 07, 2000 16:13
> > > To: 'gundam@aeug.org'
> > > Subject: RE: [gundam] Gravity within a colony (was: Funnels and flying
> > > MS)
> > >
> > > So in calculated a colonies' rotation with a radius of 500 meters I
would
> > > do it as so:
> > > Calculate circumference (2 * Pi * 500 meters) = 2 * 3.14 * 500m =
3,149.59
> > > meters
> > >
> > > then velocity if colony surface^2 (gravity * radius) = 9.8m/s * 500m
=
> > > 4,900m^2/s
> > >
> > > then take the sq root of the velociy = 4,900m^2/s = 70 m/s
> > >
> > > so the time for one revolution would be (circumference / velocity) =
> > > 3,149.6m / 70m/s
> > >
> > > this comes to 44.88 seconds for one revolution. Is this incorrect?
> >
> > It sounds about right to me. A radius of 895 meters (diameter of 1.79
km)
> > rotated at 1 RPM yields exactly 1 G at the rim, so a radius of 500
meters
> > (diameter of 1 km) should rotate at about 1.34 RPM to achieve the same
effect
> > and 1.34 RPM = 1 R every 44.8 minutes.
>
> Oops! Typo  that should be 44.8 seconds (1.34 RPM / 60 seconds).
>
> Conversely, 60/44.8 = 1.339285714....
>
> Z
>
>
> 
> Gundam Mailing List Archives are available at http://gundam.aeug.org/
Check the math and basic physicsan object that large rotating that fast
would produce 83,883 gs!
Acceleration = w*r^2; w = (2*Pi)/60 seconds = .1047 rad/s. r^2 = 801025...
Mark Wilson

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