-Z- (z@gundam.com)
Tue, 7 Nov 2000 22:47:30 -0800


> -----Original Message-----
> From: owner-gundam@1u.aeug.org [mailto:owner-gundam@1u.aeug.org]On
> Behalf Of -Z-
> Sent: Tuesday, November 07, 2000 22:29
> To: gundam@aeug.org
> Subject: RE: [gundam] Gravity within a colony (was: Funnels and flying
> MS)
>
>
> > -----Original Message-----
> > From: owner-gundam@1u.aeug.org [mailto:owner-gundam@1u.aeug.org]On
> > Behalf Of Vince Leon
> > Sent: Tuesday, November 07, 2000 16:13
> > To: 'gundam@aeug.org'
> > Subject: RE: [gundam] Gravity within a colony (was: Funnels and flying
> > MS)
> >
> > So in calculated a colonies' rotation with a radius of 500 meters I would
> > do it as so:
> > Calculate circumference (2 * Pi * 500 meters) = 2 * 3.14 * 500m = 3,149.59
> > meters
> >
> > then velocity if colony surface^2 (gravity * radius) = 9.8m/s * 500m =
> > 4,900m^2/s
> >
> > then take the sq root of the velociy = 4,900m^2/s = 70 m/s
> >
> > so the time for one revolution would be (circumference / velocity) =
> > 3,149.6m / 70m/s
> >
> > this comes to 44.88 seconds for one revolution. Is this incorrect?
>
> It sounds about right to me. A radius of 895 meters (diameter of 1.79 km)
> rotated at 1 RPM yields exactly 1 G at the rim, so a radius of 500 meters
> (diameter of 1 km) should rotate at about 1.34 RPM to achieve the same effect
> and 1.34 RPM = 1 R every 44.8 minutes.

Oops! Typo -- that should be 44.8 seconds (1.34 RPM / 60 seconds).

Conversely, 60/44.8 = 1.339285714....

-Z-
 

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